Answers

2015-10-09T18:30:55+05:30
Cv of LPG = 55 kJ/g
When 1g is used, 55kJ is produced.
time = 11sec

power = 55/11 = 5kW

answer is A.
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  • Brainly User
2015-10-09T18:35:33+05:30
A burner consumes one gram of LPG in 11 sec. What is the power of consumption of burner in KW if Cv of LPG is 55 kJ/g. a 5 kW
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