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2015-10-10T13:12:21+05:30

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Ans. (b) Energy supplied to the engine = 196 1
Mass of water= 500 gm = 500/1000 = 1/2 kg
Acceleration due to grom1d (g) = 10 mtlsec
2.Energy required for lifting water= mgh
H =energy supplied I m x g = 196 x 2 I 1 x 10 = 39.2 mt.
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2015-10-10T15:28:53+05:30

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Energy = 196 J
mass = 500g = 0.5 kg
let the height = h

Potential energy = mgh
196 = 0.5*10*h
h = 196/5 = 39.2 m

answer is B
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