Answers

2015-10-10T20:36:21+05:30
Let 2^a=3^b=6^c =k 

2 = k^(1/a), 3 = k^(1/b) and 6= k^(1/c) 

2*3=6 
k^(1/a)*k^(1/b) = k^(1/c) 

k^(1/a +a/b)= k^(1/c) 

1/a +a/b = 1/c 

a+b/ab = 1/c 

c= ab/a+b Hence, Proved.
0