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2015-10-12T22:38:59+05:30

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2r³ + 9r² - 135 = 0
⇒ 2r³ - 6r² + 15r² - 45r + 45r - 135 = 0
⇒ 2r²(r-3) + 15r(r-3) + 45(r-3) = 0
⇒ (r-3)(2r² + 15r + 45) = 0

Thus
1. r-3 = 0
⇒r = 3

2. 2r² + 15r + 45 = 0
This doesn't have real solution.

So the value of r is 3.


1 5 1
not understanded
please explain
Factorise the polynomial.