Answers

2014-06-22T20:07:47+05:30
Let one side of triangle on X-axis
 co ordinate of each point of triangle is
A = (0,0)
B = (1,0)
C = (1/2,√3/2)
X1 = (0*1+1*2+3*1/2)/(1+2+3)
     = 7/12
Y1 = (0*1+0*2+3*√3/2)/(1+2+3)
     = 3√3/12
     = √3/4
hence centre of mass = (X1,Y1) = (7/12,√3/4)
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