Answers

2015-10-14T17:08:25+05:30
The total height of tree is 10 m
Then one part is x m
And, the other part will be (10-x)
The broken part forms the hypotenuse and the part firmed to the ground is the perpendicular.
sin60°=p/h
√3/2=x/10-x
10√3-√3x=2x
(10*1.73)-1.73x=2x
17.3=2x+1.73x
17.3=3.73x
1730/373=x
4.68=x

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2015-10-14T17:35:28+05:30
Let the tree be AB with its top A so 
AB=10 m
now it bents and touch the ground so let that point be C   making angle 90 with ground
now it became a triangle ABC
in triangle ABC  angle B=60
now sin 60 = √3/2
also sin 60 =opp/Hypo
 ⇒√3/2=opp / 10
⇒opp=5√3

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