# A hammer of tje mass 1kg strikes on the head of a nail with a velocity of 2m/s .it drives the nail 0.01m into a wooden block. Find the force applied by the hammer and the time of impact.

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by crmail

by crmail

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Mass m= 1kg

initial velocity u=2m/s

distance covered s=0.01m

so applying equation of motion

V²=U²+2as

here v=0

a=4/(2*0.01)

=200m/s²

so Force F=ma

m is mass and a is acceleration

F=1*200=200N

V=u+at

So time of impact t is

0=2+200t

t=2/200=0.01s or 1 milisecond

initial velocity u=2m/s

distance covered s=0.01m

so applying equation of motion

V²=U²+2as

here v=0

a=4/(2*0.01)

=200m/s²

so Force F=ma

m is mass and a is acceleration

F=1*200=200N

V=u+at

So time of impact t is

0=2+200t

t=2/200=0.01s or 1 milisecond

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.

mass of hammer, M = 1kg

initial velocity, u = 2m/s

final velocity, v = 0

distance covered, s=0.01m

v² - u² = 2as

⇒ 0 - 2² = 2*a*0.01

⇒ -4 = 0.02a

⇒ a = -4/0.02 = -200 m/s²

time = (v-u)/a = (0-2)/(-200) = 0.01 second

Force = ma = 1*200 = 200N

initial velocity, u = 2m/s

final velocity, v = 0

distance covered, s=0.01m

v² - u² = 2as

⇒ 0 - 2² = 2*a*0.01

⇒ -4 = 0.02a

⇒ a = -4/0.02 = -200 m/s²

time = (v-u)/a = (0-2)/(-200) = 0.01 second

Force = ma = 1*200 = 200N

Time = 0.01 sec.

Force = 1 kg * 2 m/s / 0.01 s = 200 Newtons