# How can I solve completing square method? My sum is 2xsq-7x+3=0

2
by Simli

2015-10-15T11:18:38+05:30
Now we can solve a Quadratic Equation in 3 steps:
Step 1 Divide all terms by a (the coefficient of x2).
Step 2 Move the number term (c/a) to the right side of the equation.
Step 3
Complete the square on the left side of the equation and balance this by adding the same value to the right side of the equation.
Thanks but I'm not getting the idea to solve
Minus 3 by 2 plus 49 by 16 =? How ?? To do??
2015-10-15T13:44:51+05:30
2x² - 7x + 3 = 0

Divide all terms by 2 (the coefficient of x²).
⇒ (2x² - 7x + 3)/2 = 0

⇒ x² - 7x/2 + 3/2 = 0

Move the constant term to the right side of the equation.
⇒ x² - 7x/2 = -3/2

Add the b² term on both sides.
⇒ x² - 2*x*7/4 + (7/4)² = -3/2 + (7/4)² = -3/2 + 49/16

Complete the square on the left side of the equation.
⇒ (x - 7/4)² = (-24+49)/16 = 25/16

⇒ (x-7/4)² = (5/4)²

find the square root.
⇒ x - 7/4 = +- 5/4

⇒ x = 7/4 +- 5/4

⇒ x = 7/4+5/4 and 7/4-5/4

⇒ x = 3 and 1/2