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In the figure attached the

angle 1 = angle2

CE bisects BF

BD = DF

prove that angle C = angle E

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by VishitM

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angle 1 = angle2

CE bisects BF

BD = DF

prove that angle C = angle E

by VishitM

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The Brainliest Answer!

side BD = side DF (given)

angle CDB = angle FDE (vertically opposite angles)

angle CBD = angle EFD (linear pair of angles)

therefore by SAA test triangle BCD is congruent to triangle DEF

THEREFORE ANGLE C = ANGLE E (CORRESPONDING ANGLES OF CONGRUENT TRIANGLES)

Taking ΔBCD and ΔDEF,

side BD = side DF (given)

angle CDB = angle FDE (because they are vertically opposite angles)

angle CBD = angle EFD (because they linear pair of angles)

.·. According to SAA (side angle angle)

ΔBCD ≡ ΔDEF

As they are congruent

Angle C = Angle E (Hence, proved)