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2015-10-16T13:42:31+05:30

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Husband's age = X  years.                  four years ago:  X - 4 yrs
wife's age = Y yrs                              four yrs ago = Y - 4 yrs

Let them have  N children.

Let sum of ages of their children = Z  yrs
       this age four years ago = Z - 4 * N  yrs
       this age after 2 yrs from now :  Z + 2 * N  years

Given
         X + Y = 4 * Z          ---- (1)

Four years ago:
        [ (X-4) + (Y-4) ] :  (Z - 4* N)  =  18  :  1
        (X + Y - 8) = 18 (Z - 4 * N)
         X + Y  = 18 Z - 72 N  + 8        --- (2)

from (1) and (2):
         14 Z + 8 =  72 * N
         N = (7 Z + 4)/ 36      --- (3)

As  N is an integer,   7 Z + 4 = 36 or 72 or 108 or 144  or 180 ...
         Then  Z =  20     for  7 Z + 4 = 144.
         Then N = 4

So  X + Y = 80   from (1)

Two years from now:
     sum of ages of parents = X+2+Y+ 2  = 84  yrs
   sum of ages of  children =  20 + 2 * 4 =  28 years

Their ratio  =  84: 28 = 3 : 1   

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they have four children... the sum of the childrens ages = 20 yrs.
sum of parents ages = 80 yrs