A point moves along a circle of radius 1m with speed v=at .The tangential acceleration of the point at a time when it has completed 1/8 of the revolution from start is ?

wtas u r question
he is asking acceleration read carefully
thanks for u r help
mntn nt :)
mine answer is coming π/4t²



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V = linear speed = a t
the linear  tangential acceleration =  dv/dt =  a  = constant at any time...

the centripetal acceleration = v² / R =  a² t² / R
   this depends on the time and continuously  increases.

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