# If the unit of length is doubled ,unit of time is halved and unit of force is quadrupled,the unit of power would change by the factor

2
by nani4

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by nani4

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w = FS where S is the length

ATQ

P = 4N × 2m / (s/2)

P = 16Nm/s

so , the power will increase by a factor of 16

Here,

Work done= F*S where F= force applied and S =distance traveled.

Now,

F₁=4F

S₁=2S

T₁=T/2

P=4F*2S/(T/2)

P=16F*S/T

P₁=16P