Answers

  • Brainly User
2015-10-20T17:17:30+05:30
 [ -b + (b^2 -4ac)^1/2 ] / 2a = 2a / [ -b - (b^2 -4ac)^1/2 ] 
[ -b - (b^2 -4ac)^1/2 ] [ -b + (b^2 -4ac)^1/2 ] = 4a^2 
b^2 - (b^2 -4ac) = 4a^2 
b^2 -b^2 +4ac = 4a^2 
c = a 
ie If a= c then roots of a quadratic equation reciprocal of each other? 
eg 3x^2 - 7x + 3 =0 
x = [ 7 + 13^1/2 ] / 6 or 6 / [ 7 - 13^1/2 ] 
1st root x 2nd root 
= 6 / [ 7 + 13^1/2 ] * 6 / [ 7 - 13^1/2 ] 
= 36 / (7^2 -13) 
= 36 / 36 
= 1 
so root 1 = 1/ root 2 QED
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