# Three brands A, B and C of biscuits are available in packets of 12, 15 and 21 biscuits respectively. If a shopkeepeer wants to buy an equal number of biscuits, of each brand, what is the minimum number of packets of each brand, he should buy?

2
by reevinodtm

2015-10-20T15:29:42+05:30

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Number of biscuits in a packet of brand A = 12
number of biscuits in a packet of brand B = 15
number of biscuits in a packet of brand C = 21

Find the LCM of 12,15 and 21
12 = 2×2×3 = 2²×3
15 = 3×5
21 = 3×7
LCM = 2²×3×5×7 = 420

So number of biscuits of each brand = 420
Packets of brans A = 420÷12 = 35
Packets of brans B = 420÷15 = 28
Packets of brans C = 420÷21 = 20
2015-10-20T22:37:47+05:30
In this u need to find to L.C.M
therefore it is:
12=2×2×3
15=3×5
21=3×7

which is therefore 3×2×2×7×5=320
sorry it should be 420