# If two zeroes of the polynomial x⁴-5x³+3x²+15x-18are √3 and √3 then find the remaining zeroes

2
by 012345
is it root 3 and -root3...chck tht qstn dude nce
.sry it is -√3 and √3
xcuze rply fast
ok

2015-10-20T15:59:33+05:30

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Too easy yaar
first we have twoo roots √3 and -√3 right
we can write them as (x-√3) and (x+√3)
mulitply both these to get a polynimial
it is in the form of (a+b) and (a-b) = a²-b² this == x²-3
Now divide the polynomial x⁴-5x³+3x²+15x-18 with x²-3we get quotient as x²-5x+6
on factorising it we get factors 3 and 2
Therefore answer is √3,-√3,3 and 2
Nice!! wrote the procedure well!
thnkz yaar
thank u
c fr this qstn TPS my ans=== link-- http://brainly.in/question/210021
2015-10-20T16:02:25+05:30

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Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
Two zeroes are √3 and -√3
So two factors are (x-√3) and (x+√3)

(x-√3)(x+√3) = x² - 3
x² - 3 is a factor of x⁴-5x³+3x²+15x-18

Now. divide x⁴-5x³+3x²+15x-18 by x²-3
You will get (x² - 5x + 6)

Now find the zeroes of x² - 5x + 6 = 0
⇒ x² - 5x + 6 = 0
⇒ x² - 2x -3x + 6 = 0
⇒ x(x-2) -3(x-2) = 0
⇒ (x-3)(x-2) = 0
⇒ x-3 = 0     and      x-2 = 0
⇒ x = 3    and    x=2

Other two zeroes are 2 and 3.
good 1 yaaro
thanks!
thank u
U r welcome!