# A water tank can be filled by a ta in 8 hours and emptied by an outlet pipe in 12 hours. How long it will take to fill the cistern if both the tap and the pipe are opened together

2
by bhuvanarvind

2015-10-20T19:29:20+05:30

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Work done by tap in 1 hour= (1/8) part.
work done by outlet pipe in 1 hour=(1/12) part.
work done by both=(1/8)-(1/12)
=(3-2)/24
=(1/24) part.
therefore,hours required for the tank to be filled=1÷(1/24)
=24 hours.
2015-10-20T21:32:36+05:30

### This Is a Certified Answer

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
Tank filled in 1 hour = 1/8 th part
tank emptied in one hour = 1/12th part

in 1 hour, effective filling = 1/8 - 1/12 = (3-2)/24 = 1/24 th part
for complete filling, time = 1/(1/24) = 24 hour