Answers

2015-10-25T19:39:05+05:30
According to the problem ,the series is arithmetic with nth term 3n+1 The maximum n for which nth term will be two digit is 10. The sum is = 3×(n ×(n+1)/2)+n n=10 So sum = 3×10×11/2 +10 =165+10=175
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