Answers

2015-10-27T02:22:06+05:30
Let the no of toys be x and price of each toy be y
therefore, xy = 360
and x=360/y  {eg -1}
2nd condition
(x+2)(y-2)=360
xy + 2y - 2x - 4 = 360
2y - 2(360/y) - 4 = 0  { since xy=360 & from eq 1}
 2y^{2} - 4y -720 = 0
 y^{2} - 2y - 360 =0
 y^{2} - 20y +18y -360 =0
y(y-20) +18(y-20) = 0
(y+18)(y-20)=0
therefore y= -18 or y = 20
in this case y=20 since price of quantity cannot e in negative
therefore the original price of toy is 20 rupees

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