Answers

2015-10-27T11:45:59+05:30
Follow these steps --->
1)Draw line segment QR of 6 cm. At point Q, draw an angle of 60°, say ∠XQR.
2)Cut a line segment QS of 2 cm from the line segment QT extended in the opposite side of line segment XQ. (As PR > PQ because PR − PQ = 2 cm). Join SR.
3)Draw perpendicular bisector AB of line segment SR. Let it intersect QX at point P.Now,Join PQ, PR.
Triangle formed.
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