Answers

2015-10-28T11:23:12+05:30
(2p + 1)x² + (7p+2)x + (7p-3) = 0
If they have equal roots,
b²-4ac=0
Let,
a=2p+1
b=7p+2
c=7p-3
Now,
(
7p+2)² - 4(2p + 1) (7p-3)=0 
49p² +4+ 28p – 4(14p² +p-3)=0
After simplification,
7p²-24p+16=0 
The roots are,
4 and -4/7.


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