Answers

2014-06-25T20:16:07+05:30
The answer is the HCF of all these numbers, because HCF can divide all of them [its a factor of all of them].  Thus, the required flask is of volume of 23 L.
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2014-06-25T22:38:50+05:30
Do HCF of all these numbers, because HCF can divide all of them [its a factor of all of them].  
Thus, the required flask is of volume of 23 L
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