# A particle of mass g is thrown vertically upwards with a speed of 5 m/s.what is the work done by the force of gravity during the time the particle goes up?

2
by zaharacutie

2015-10-27T19:43:15+05:30

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it is given that ,
mass of the object = g

initial velocity = 5 m/s
final velocity = 0 m/s
acceleration due to gravity = -10 m/s^2 ( it is -10 m/s^2 since it is in the opposite direction to the gravity )
2as = v^2-u^2
2(-10)(s) = 0^2 - (5)^2
-20s = -25
s = -25/-20
s = 1.25 m
work done = force * displacement
work done = mass * acceleration * 1.25
work done = g * -10 * 1.25
work done = -12.5 * g
therefore the work done by the gravity is -12.5 * g J.( work done will be 12.5 times the g means the mass but in -ve since the motion is in opposite direction to the force applied )
i hope that this will help u........................^_^

g is 9.8m/s raise to 2 no
ya but we can use 10 m/s^2 also because if we round off 9.8 we get 10 m/s^2 it is used to make calculation easier.
2015-10-27T21:24:19+05:30

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Use conservation of energy theorem. It will be easier.
PE at top point = initial KE
⇒ PE = 1/2mv² = 1/2 × g × 5² = 12.5 g

Potential energy = -(work done by gravity)
So work done by gravity = -12.5g