Answers

2015-11-10T09:07:37+05:30
Finding the root by completing square method
for this let us take a quadratic equation ax^2+bx+c=0
step 1 :-
Reduce the coefficient of x^2 to 1
a(x^2+(b/a)x+c/a)=0
step 2 :-
now add and subtract the square of the half of the value
x^2+(b/a)x+c/a+(b/2a)^2-(b/2a)^2=0
step 3 :-
now make the formula of either (a+b)^2 or (a-b)^2 according to the equation
[x^2+(b/a)^2+(b/a)] - (b/2a)^2+c/a
step 4 :-
after making the formula add the remaining digits and try to write them in the term of their perfect square
[x+(b/a)]^2 +[c/a+(b/2a)^2]
on solving
[x+(b/a)]^2+ [sqrt(c+b^2)/sqrt(2a)]=0

finding rooys of square by firmula method
let us consider a quadratic equation ax^2+bx+c

D=b^2-4ac
x=[-b+sqrt(D)]/2a
and
x=[-b-sqrt(D)]/2a

Hope it helps

0
b/a wale coefficient ke sath x bhi hai aur aur main x ke coefficient ki bat kar raha hu in step 2.plz don't mind