# Sushil is now 4 times as old as sunil. five years ago sushil was 7 times as old as sunil was then. find the present age of each of them?

2
Log in to add a comment

Log in to add a comment

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.

Let the age of Sunil be `x` yrs

Then the age of sushil = 4x years

five years ago sunil`s` age = (x - 5) years

And Sushil`s age five years ago = (4x - 5) years

But ti is given that five years ago the age of sushil is 7 times of sunil`s age

⇒7(x - 5) = 7x - 35

∴7x - 35 = 4x - 5

⇒7x - 4x = -5 + 35

⇒3x = 30

⇒x = 30/3

∴x = 10 years

Sunil`s age = x = 10 years

and Sushil`s age = 4x = 4* 10

=40 years.

Then the age of sushil = 4x years

five years ago sunil`s` age = (x - 5) years

And Sushil`s age five years ago = (4x - 5) years

But ti is given that five years ago the age of sushil is 7 times of sunil`s age

⇒7(x - 5) = 7x - 35

∴7x - 35 = 4x - 5

⇒7x - 4x = -5 + 35

⇒3x = 30

⇒x = 30/3

∴x = 10 years

Sunil`s age = x = 10 years

and Sushil`s age = 4x = 4* 10

=40 years.

Sushil age = 4x

Five years ago

Sunil age = x - 5

Sushil age = 4x - 5

Given that

4x - 5 = 7(x - 5)

4x - 5 = 7x - 35

3x = 30

x= 10

Sunil age = 10

Sushil age = 40