# Divide 56 in to two parts such that three times the first part exceeds one third of the second by 48 .The parts are.

2
by sopShrresh

2015-10-28T22:12:35+05:30

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Hi there,
let the first part be x
there fore according to the question 3x-(56-x)/3=48
(9x-56+x)/3=48
10x-56=144
10x=200
x=200/1=20
so the first part is 20 and the second part is 56-20=36
i hope this helps u...
2015-10-28T23:49:12+05:30

### This Is a Certified Answer

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
Let first part be x
then the second part be............
According to the question,
3x-(56-x)/3=48
(9x-56+x)/3=48
10x-56=144
10x=144+56
x=200/10
x=20
therefore, second number will be = 56-x
=56-20
=36