# A straight line, AB, undergoes two reflections. First reflection occurs in a mirror, placed in the vertical plane at x=0. The reflected line undergoes another reflection, in another mirror, placed in the horizontal plane at y=0. If the x and y intercepts of line AB are p and q respectively before the reflections, then the equation of the line after the second reflection will be:

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by rohitkotwal1993

2015-10-31T05:05:13+05:30

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The equation of the given line AB =  x/p  + y/q = 1

Equation of line after one reflection in the vertical mirror :
x/-p  + y/q = 1

equation of line after 2nd reflection, of the reflected rays, from the horizontal mirror
x/-p  +  y/-q =  1
=>   x/p + y /q  = -1

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