Answers

2015-10-31T13:13:35+05:30
Let the original fraction be X/y Given X=y-6, so the fraction can be written as y-6/y and given if 3 is added to numerator then fraction becomes 2/3 so the fraction is y-6+3/y=2/3--->y-3/y=2/3---->3(y-3)=2y--->3y-2y=9--->y=9 so the fraction is y-6/y=9-6/9=3/9=1/3.
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2015-10-31T13:28:35+05:30
Hi there,
let the denominator be x
so the fraction =x-6/x
so  x-6+3/x=2/3
=x-3/x=2/3
3(x-3)=2x
=3x-9=2x
x=9
therefore the fraction =9-6/9
=3/9=1/3
i hope this helps u...
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