Answers

2015-10-31T15:21:41+05:30
Hi there,
(x+1)is a factor of x^3-3x^2-9x-5
so x^3-3x^2-9x-5=x^2-4x-5
x^2-4x-5=(x+1)(x-5)
there fore x^3-3x^2-9x-5=(x+1)^2(x-5)
i hope this helps u...
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2015-10-31T15:22:04+05:30
X³ - 3x² - 9x - 5

= x³ + x² - 4x² - 4x  - 5x - 5

= x²(x+1) - 4x(x+1) -5(x+1)

= (x+1)(x² - 4x - 5)

= (x+1)(x² - 5x + x - 5)

= (x+1)[x(x-5) + 1(x-5)]

= (x+1)[(x-5)(x+1)]

= (x+1)(x+1)(x-5)

=(x+1)²(x-5)
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