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The Brainliest Answer!
2015-10-31T18:15:38+05:30
Side of rhombus, a = 10cm
one of diagonal D= 16cm
D/2 = 16/2=8cm
let other diagonal = d

diagonals of rhombus bisect each other right angle. so a right angle triangle is formed with halves of the diagonals and side. using pythagoras theorem
a² = (D/2)² + (d/2)²
⇒ 10² = 8² + (d/2)²
⇒ (d/2) = √(10²-8²) = √36 = 6
⇒ d = 2*6=12cm

Area = Dd/2 = 16*12/2= 96cm²
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