# The ages of Leena and Heena are in the ratio 7:5 . Ten years hence, the ratio of their ages will be 9:7. find their present ages.

2
by dhananjaygudia

2015-11-01T20:01:24+05:30

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Let Leena's present age be 7x years and Heena's present age be 5x years
After 10 years,
Leena's age=7x+10
Heena's age=5x+10
7x+10+5x+10=9x+7x
20=16x-12x
20=4x
x=5

Leena's present age=7x=7×5=35
Heena's present age=5×5=25
2015-11-01T20:15:25+05:30

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Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
The ratio of the present ages of Leena and Heena = 7:5
Let the age of Leena be 7x years and Heena be 5x years
Ten years later their ages will be 7x +10 years and 5x + 10 years
but the ratio of their ages after ten years is given as 9:7
let their ages be 9x and 7x
∴9x + 7x = 7x + 10 + 5x + 10
⇒9x = -7x + 7x + 10 + 5x + 10
⇒9x -5x = 10 + 10
⇒4x = 20
⇒x = 20/4 = 5
∴The age of Leena = 7x = 7* 5 = 35 years
And Heena`s age = 5x = 5* 5 = 25 years.