Answers

2015-11-01T21:52:49+05:30

This Is a Certified Answer

×
Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
Applying Law of conservation of momentum, Pi=MV. Pf=mv₁+(M-m)v₂. Given v₁=0 => Pf=(M-m)v₂ Fext=0 ⇒Pi=Pf ⇒MV=(M-m)v₂ ⇒v₂= \frac{MV}{M-m}
0
2015-11-01T22:23:06+05:30

This Is a Certified Answer

×
Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
Before explosion,
mass of space craft = M
velocity = V
momentum = MV

after explosion,
mass of one part = m
velocity = 0
mass of other part = M-m
velocity = v = ?
momentum = m-0 + (M-m)v =(M-m)v

conserving momentum,
MV = (M-m)v
⇒ v = MV/(M-m)

∴ Velocity of other part is MV/(M-m)







2 5 2