# Calculate the total pressure in a mixture of 10 g of dioxygen and 8g of diHydrogen confined in a vessel of 2 L at 27 degree celsius.

1
by amilleshuuu

2015-11-13T01:12:38+05:30

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Volume = V = 2 L = 0.002  m³
T = 273.15 + 27 = 300.15 °K
R = 8.314 J/ mole / °K

number of Moles of Oxygen  = 10 gm / 32 gm/mol  = 5/16
number of moles of Hydrogen:  8 gm  / 2 gm/mol = 4
total number of moles in the gas mixture = 69/16

P V = n R T
P = 69/16 * 8.314 * 300.15 / 0.002      Pa
= 53.8 atm  approximately    or   5.38 * 10⁶ Pa

It seems a lot,  for just 18 gms of a gas mixture in a 2 L container at room temperature, exerting  5 times atmospheric pressure.
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