# If sin C = 15/17, then my dear frnds can u plz find cosC

2
by pallelanamrath

2015-11-04T23:00:27+05:30

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SinC =15/17 = opposite/hypotenuse CosC= Adjesent /hypotenuse In tri.ABC AC°2 =AB°2+BC°2 17°2=15°2+BC°2 289=225+bc^2 BC°2= 64 BC=8 CosC=8/17
2015-11-04T23:04:39+05:30

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Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
Given :- sin c = 15/17
But we know that, sin θ = p/h = perpendicular/ hypotenuse
Therefore, p = 15 and h = 17
By Pythagoras Theorem,
h² = p² + b²
(17)² = (15)² + b²
289 = 225 + b²
289 - 225 = b²
b² = 64
b = √64
b = √8 * 8
b = 8
So, cos θ = b/h
Therefore, cos c = 8/17
Its my pleasure freind