Answers

2015-11-07T12:55:32+05:30
IN THE ADJACENT FIGURE
DECF IS ARECTANGLE SO DE=CF⇒1
AS,DC||Ab,AB IS A TRANSVERSALSO ANGLE AED=ANGLEBFC⇒2GIVEN AD=BC⇒3
FROM1,2,3
BY RHS congruency
triangleAED=TRIangleDFC
BY CPCT
ae =bf
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