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In ∆DAY & ∆CBX

since , Ax = BY (given) ,so , AX + XY = BY + XY , so AY = BX

DA = CB (GIVEN)

& ∠DAY = ∠CBX (90°)

By , SAS , they are congruent

since , Ax = BY (given) ,so , AX + XY = BY + XY , so AY = BX

DA = CB (GIVEN)

& ∠DAY = ∠CBX (90°)

By , SAS , they are congruent

### This Is a Certified Answer

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.

*given,*

DA = CB

AX = BY

to prove :- ΔDAY ≈ ΔCBX

DA = CB

AX = BY

to prove :- ΔDAY ≈ ΔCBX

__proof:-____DA = CB__

__∠A = ∠B = 90°__*AX = BY*

therefore,

therefore,

*AX + XY = BY + XY*

__AY = BX__(∵ if equals are added to equals the wholes are equal)

**therefore ΔDAY ≈ ΔCBX***by SAS congruence rule*

*.*

*i hope that this will help u.......................^_^*