# When a ball is thrown vertically upwards it goes through a distance of 19.6 mfind the initial velocity of ball and time takenbu to rise the highest point

2
by knk

2015-11-08T21:05:08+05:30

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Let initial velocity = u m/s
time taken to rise to highest point = t second
final velocity at highest point = 0
g = -9.8 m/s²
distance travelled = 19.6 m

d = (v² - u²)/2a
⇒ 19.6 = (0 - u²)/2×(-9.8)
⇒ 19.6 = u²/19.6
⇒ u² = 19.6×19.6
⇒ u = 19.6 m/s

v = u+at
⇒ 0 = 19.6 - 9.8t
⇒ 9.8t = 19.6
⇒ t = 19.6/9.8
⇒ t = 2s

Initial velocity = 19.6 m/s
time taken to reach highest point = 2s
2015-11-08T21:11:57+05:30

### This Is a Certified Answer

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
H = 19.6 m

g = - 9.8 m/s²

Since it has to reach at the highest poing where v = 0 ,

using ,

v²-u² = -2gh
b
u² = 2gh

u² = 2gh = 2×9.8×19.6

u = 19.6m/s

Since , also ,

v = u+gt

0 = -3+a 9.8 ×t

t = 19.6/9.8

t = 2 s