# David and Joseph have a total of 328 marbles. Matthew and David have 178 marbles. Joseph has 5 times as many marbles as Matthew. How many marbles does David have?

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perhaps joseph as 6 times as many as mathew

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perhaps joseph as 6 times as many as mathew

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Lets assume David as D,Joseph as J and Matthew as M

D+J=328 ..........given

M+D=178..........given

and j=6XM ...........(its maybe 6 times as many as marbles as matthew, 5 gives fractional values which is not true for counting object , we always used natural number for counting.....nobody count like 1,1.1 etc....its creates problem )

6XM+D=328

M+D=178

- - - (minus sign)

---------------------

6M-M+D-D=328-178

5M=150

M=30

J=6M=6*30

J=180

D=328-J=328-180=148

David=148 Marbles

D+J=328 ..........given

M+D=178..........given

and j=6XM ...........(its maybe 6 times as many as marbles as matthew, 5 gives fractional values which is not true for counting object , we always used natural number for counting.....nobody count like 1,1.1 etc....its creates problem )

6XM+D=328

M+D=178

- - - (minus sign)

---------------------

6M-M+D-D=328-178

5M=150

M=30

J=6M=6*30

J=180

D=328-J=328-180=148

David=148 Marbles

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.

Let david & joseph has x & y marbles , let mathew has z ,

now ,

ATQ :-

x + y = 328 ---(1)

z + x = 178 ----(2)

also , y = 5z

Putting y = 5z in eq.(1)

x + 5z = 328

x + z = 178

- - -

4z = 150

z = 150/4 ,

Now putting z in eq.2

150/4 + x = 178

x = 140.5 ~ 141 marbles

now ,

ATQ :-

x + y = 328 ---(1)

z + x = 178 ----(2)

also , y = 5z

Putting y = 5z in eq.(1)

x + 5z = 328

x + z = 178

- - -

4z = 150

z = 150/4 ,

Now putting z in eq.2

150/4 + x = 178

x = 140.5 ~ 141 marbles