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2015-11-10T08:59:03+05:30

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Lets assume David as D,Joseph as J and Matthew as M
D+J=328 ..........given
M+D=178..........given
and j=6XM ...........(its maybe 6 times as many as marbles as matthew, 5 gives fractional values which is not true for counting object , we always used natural number for counting.....nobody count like 1,1.1 etc....its creates problem )
6XM+D=328
M+D=178
-   -    -  (minus sign)
---------------------
6M-M+D-D=328-178
5M=150
M=30
J=6M=6*30
J=180
D=328-J=328-180=148

David=148 Marbles
0
2015-11-10T10:11:02+05:30

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Let david & joseph has x & y marbles , let mathew has z ,

now ,

ATQ :-

x + y = 328 ---(1)

z + x = 178 ----(2)

also , y = 5z

Putting y = 5z in eq.(1)

x + 5z = 328
x + z = 178

- - -

4z = 150

z = 150/4 ,

Now putting z in eq.2

150/4 + x = 178

x = 140.5 ~ 141 marbles

1 5 1
note that number of marbles is not a fraction... so there must be a mistake in the question... you need to mention that.
I knw that sir , Something is wrong in qsn