# The number of atoms of oxygen present in 0.2 moles of Na₂CO₃ will be what? please explain answer

2
by arjyamaan

2015-11-10T10:52:07+05:30

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1 mole of NA₂CO₃ contains = 3 moles of oxygen atom
we have 0.2 moles of NA₂CO₃ ,
so we will have = 3 * 0.2
= 0.6 mole of O atoms
since 1 mole of O atoms = 6.022 * 10²³ atoms
therefore,
0.6 mole of O atoms = 0.6 * 6.022 * 10²³
= 3.6132 * 10²³ O atoms
therefore in 0.2 moles of NA₂CO₃
number of Oxygen atoms = 3.6132 * 10²³
i hope that my answer will help u.................................^_^
thanks a lot!
ur welcome
2015-11-10T10:58:46+05:30

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1 mole of Na2CO3 contains 3 moles of oxygen atoms means 18.066* 10 ^ 23 atoms
0.2 moles of na^2co^3 contains 3.6132 * 10^23 atoms.
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