Answers

2015-11-14T22:15:42+05:30
Case 1)
lets assume all the days were of the same month, in that case
x + (x+1) + (x+2) + (x+3) + (x+4) = 63
5x = 53
x is coming out to be in decimal, which can not be.
Case 2)
now the other possibility is such that month changes after some days
thus there can be few possibilities
A) x + (x+1) + (x+2) + (x+3) + 1 = 634x = 56 => x = 14, but 1st cant come after 17th, so it is ruled out.
B) x + (x+1) + (x+2) + 1 + 2 = 63
3x = 57 => x = 19, but again 1st cant come after 21, so it is ruled out as well.
C) x + (x+1) + 1 + 2 + 3 = 63
2x = 56 => x = 28, this is possible for the month with 29 days, i.e. February of leap year.
So the dates were 28,29,1,2,3
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