The area of a circle whose radius is the diagonal of a square whose area is 4 is

2
please give me answer
6,8,16,4pai isme se ans. batana he
mera answer to 25.1 aaya hai 
square area = 4
length of each side is 2
by pythagoras theorem....diagonal length is  \sqrt{8} 
radius =  \sqrt{8} 
area of circle  =  \pi  r^{2} 
25.132

Answers

2015-11-15T20:45:02+05:30

This Is a Certified Answer

×
Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
Hi there,

area of square =4
so by Pythagoras theorem the diagonal =√8=radius 
area of the circle=πr^2=25.132
i hope this helps u...
 
0
2015-11-15T20:48:11+05:30

This Is a Certified Answer

×
Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
the area of the square = 4 
therefore length of each side is ,
area = side *side
4 = side *side
2*2 = side *side
therefore length of 1 side = 2
diagonal of a square = side * 
√2
= 2 √ 2 
A.T.Q ,
diagonal of square = radius of the circle 
area = 
πr²
area = 22/7 * 2√2 * 2√2
area = 22/7 * 2 * 2 * 2
area = 22/7 * 8
area = 25 .132 
therefore the answer is 25.132 
     i hope that this will help u.....................^_^


2 4 2