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Hi there,

area of square =4

so by Pythagoras theorem the diagonal =√8=radius

area of the circle=πr^2=25.132

i hope this helps u...

area of square =4

so by Pythagoras theorem the diagonal =√8=radius

area of the circle=πr^2=25.132

i hope this helps u...

### This Is a Certified Answer

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.

**the area of the square = 4**

therefore length of each side is ,

therefore length of each side is ,

**area = side *side**

4 = side *side

2*2 = side *side

therefore length of 1 side = 2

diagonal of a square = side *

4 = side *side

2*2 = side *side

therefore length of 1 side = 2

diagonal of a square = side *

**√2**

**= 2**

**√ 2**

**A.T.Q ,**

diagonal of square = radius of the circle

area =

diagonal of square = radius of the circle

area =

**πr²**

**area = 22/7 * 2**

**√2 * 2√2**

**area = 22/7 * 2 * 2 * 2**

area = 22/7 * 8

area = 25 .132

therefore the answer is 25.132

i hope that this will help u.....................^_^

area = 22/7 * 8

area = 25 .132

therefore the answer is 25.132

i hope that this will help u.....................^_^

length of each side is 2

by pythagoras theorem....diagonal length is \sqrt{8}

radius = \sqrt{8}

area of circle = \pi r^{2}

25.132