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Find the displacement of a car which increases its speed from 20 m/s to 80 m/s

in 12 second.

2
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in 12 second.

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A = (v - u)/t

so a= (80 - 20)/12

a = 5 m/s²

s = ut + 1/2 at²

s = 20×12 + 1/2× 5 × 144

s = 600 mtrs answer

so a= (80 - 20)/12

a = 5 m/s²

s = ut + 1/2 at²

s = 20×12 + 1/2× 5 × 144

s = 600 mtrs answer

Given :- u = 20 m/s and v = 80 m/s and t = 12 seconds

Therefore acceleration = (v - u)/t = (80 - 20)/12 = 60/12 = 5 m/s^2

Now applying the formula s = ut + 1/2 at^2

s = { (20 * 12) + (1/2 * 5 * 12 * 12) } m

s = { (240) + (360) } m

s = 600 m = 0.6 Km

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