Something is wrong in your question...Please check it....!

Log in to add a comment

Something is wrong in your question...Please check it....!

Log in to add a comment

If 1 is the zero of the polynomial p(x) then:-

p(1) = 2(1)^3 -3(1) +7(1) + 6

p(1) = 2(1) - 3 + 7 +6

p(1) = 2-3+7+6 = 12

As p(1) is not equal to 0. Therefore, 1 is not the zero of polynomial p(x).

P(1)=2-3+7+6=12
so x=1 is not a root of the p(x)=2xcube-3x+7x+6