# Sudesh is twice as old as Seema.If six years is subtracted from Seema's age and foyr years are added to Sudesh's age,Sudesh will be four times Seema's age.How old were they 3 years ago

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4(y-6) = 4+x

4y-24 = 4 + 2y

2y = 28

y = 14, x = 28

They were 11 and 25 three years ago.

Hope I helped you! :)

4y-24 = 4 + 2y

2y = 28

y = 14, x = 28

They were 11 and 25 three years ago.

Hope I helped you! :)

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.

Let age of seema be 'X' yrs..
Therefore age of sudesh will be 2x years
6 yrs are subtracted from seema age
Therefore seema age = x-6 yrs
4 yrs are added to sudesh age
Therefore sudesh age will be = 2x + 4 yrs.
Then.. We get 2x+4=(x-6) × 4
2x+4=4x-24
We get X=14
Therefore seema age = 14 yrs
Before 3 yrs , her age = 11 yrs
Therefore sudesh age = 28 yrs
Before 3 yrs = 25 yrs