Answers

2015-11-20T15:32:54+05:30
Let the three numbers in AP are  a-d, a, a+d where d is the common difference
Their sum = -3
a-d+a+a+d = -3
3a = -3
a = -1
their product = 8
(a+d)(a)(a+d) = 8

a(a²-d²) = 8
(-1)(1-d²) = 8
1-d² = -8
d² = 9
d = +3 or -3

Numbers are when d = -3
(-1+3), -1, (-1-3)  = 2, -1, -4
Numbers are when d = 3
(-1-3), -1, (-1+3)  = -4, -1, 2
1 4 1