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## Answers

= [sin^2A + (1 + cosA)^2]/sinA(1 + cosA)

= (sin^2A + 1 + cos^2A + 2cosA)/sinA(1 + cosA)

= (1 + 1 + 2cosA)/sinA(1 + cosA) [since,sin^2A + cos^2A = 1]

= (2 + 2cosA)/sinA(1 + cosA) = 2(1 + cosA)/sinA(1 + cosA)

= 2/sinA = 2 cosecA [since 1/sinA = cosecA] = R.H.S.

Proved