Answers

2014-07-03T17:45:13+05:30
(x²+x+1)/{(x-1)(x-2)(x-3)} = A/(x-1) + B/(x-2) + C/(x-3)
                                    = {(A+B+C)x²+(-5A-4B-3c)x+(6A+3B+2C)}/{(x-1)(x-2)(x-3)}
     compare the coefficient of power of x both side
A+B+C=1   --------------(1)
-5A-4B-3C=1  --------------(2)
6A+3B+2C=1  --------------------(3)
on solving three equation we get ,
A=3/2  B=-7  C=13/2
hence partial fraction = 3/2(x-1) - 7/(x-2) + 13/2(x-3)

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