Answers

2014-07-03T17:51:25+05:30
(7x-1)/(x²-5x+6) = (7x-1)/{(x-2)(x-3)}
                       = A/(x-2) + B/(x-3)
                     = {(A+B)x - (3A+2B)}/{(x-2)(x-3)}
compare the coefficient of power of x 
A+B = 7 ----------(1)
3A+2B = 1 --------------(2)
on solving the both equation we get ,
A=-13   B=20
hence partial fraction is
 = -13/(x-2) + 20/(x-3)
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