Answers

2014-07-03T18:00:15+05:30
Let theta = Ф
tanФ/(1-cotФ) + cotФ/(1-tanФ)
on resolving sin and cos 
=> sin²Ф/{cosФ(sinФ-cosФ)} - cos²Ф/{sinФ(sinФ-cosФ)}
=> {sin³Ф-cos³Ф}/{(sinФ-cosФ)sinФcosФ}
=> {(sinФ-cosФ)(sin²Ф+cos²Ф+cosФsinФ)}/{cosФsinФ(sinФ-cosФ)}
=> (1+cosФsinФ)/(cosФsinФ)                                                           (sin²Ф+cos²Ф=1)
=> secФcosecФ+1
put Ф=theta
cosec(theta)sec(theta)+1
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