Answers

2015-11-28T14:49:46+05:30
The number of electrons drifted in the circuit is 5.625 × 10^20.
0
2015-11-28T16:27:11+05:30
⇒ I = 50 × 10^-3 A

⇒ t = 1800 s

⇒ I = q/t

⇒ I = ne/t


⇒n = It/e

⇒ n = 50 × 10^-3 × 1800 / 1.6 × 10^-19

⇒n = 5.6 × 10^20
0