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1.let A(x1,y1)
now applying midpoint theorem,
x1 +x2=4,
x2+x3=8,and x1 +x3= -2
solving ,
x1= -3, x2= 7 , x3= 1
similarly, y1= -7, y2=9 and y3= 1
so points are A(1,-7), B(7,9) , C(1,1)
2. perimeter of triangle will be AB +BC +CA
by distance formula,
AB= 4, BC =3 and CA=5
so perimeter = 12 unit
3.equation of line parallel to 4x+5y+3=0 will be 4x+5y+c=0,
putting the value (1,2), 
c= -14
so the equation of line will be 4x+ 5y -14=0

hope u got the answer :)
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